Year 5 fractions worksheet answers to download as PDF

These Year 5 fractions worksheet answers give a full worked solution to all 20 questions of the fractions: equivalent, mixed numbers and improper worksheet. Try each question yourself first, then check your method step by step.

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Answer to Question 1
1. \(\frac{2}{3}\): the denominator is multiplied by 4, so multiply the numerator by 4 too: 2 × 4 = 8. \(\frac{2}{3}\) = \(\frac{8}{12}\).
2. \(\frac{7}{8}\): the denominator is multiplied by 3, so multiply the numerator by 3 too: 7 × 3 = 21. \(\frac{7}{8}\) = \(\frac{21}{24}\).
3. \(\frac{3}{5}\): the denominator is multiplied by 4, so multiply the numerator by 4 too: 3 × 4 = 12. \(\frac{3}{5}\) = \(\frac{12}{20}\).
4. \(\frac{5}{6}\): the denominator is multiplied by 3, so multiply the numerator by 3 too: 5 × 3 = 15. \(\frac{5}{6}\) = \(\frac{15}{18}\).
Answer to Question 2
1. \(\frac{1}{2}\) = \(\frac{2}{4}\) = \(\frac{3}{6}\) = \(\frac{4}{8}\). (Multiply top and bottom by 2, 3, 4.)
2. \(\frac{3}{4}\) = \(\frac{6}{8}\) = \(\frac{9}{12}\) = \(\frac{12}{16}\). (Multiply top and bottom by 2, 3, 4.)
Answer to Question 3
1. \(\frac{6}{8}\): divide both by 2. \(\frac{3}{4}\).
2. \(\frac{12}{18}\): divide both by 6. \(\frac{2}{3}\).
3. \(\frac{15}{25}\): divide both by 5. \(\frac{3}{5}\).
4. \(\frac{24}{36}\): divide both by 12. \(\frac{2}{3}\).
5. \(\frac{14}{28}\): divide both by 14. \(\frac{1}{2}\).
Answer to Question 4
1. 7 ÷ 4 = 1 remainder 3, so \(1\frac{3}{4}\).
2. 11 ÷ 3 = 3 remainder 2, so \(3\frac{2}{3}\).
3. 17 ÷ 5 = 3 remainder 2, so \(3\frac{2}{5}\).
4. 23 ÷ 6 = 3 remainder 5, so \(3\frac{5}{6}\).
Answer to Question 5
1. 2 × 3 = 6 and 6 + 1 = 7, so \(\frac{7}{3}\).
2. 3 × 4 = 12 and 12 + 3 = 15, so \(\frac{15}{4}\).
3. 4 × 5 = 20 and 20 + 2 = 22, so \(\frac{22}{5}\).
4. 5 × 6 = 30 and 30 + 5 = 35, so \(\frac{35}{6}\).
Answer to Question 6
1. Eighths: \(\frac{6}{8}\) and \(\frac{5}{8}\). \(\frac{3}{4}\) > \(\frac{5}{8}\).
2. Twelfths: \(\frac{7}{12}\) and \(\frac{8}{12}\). \(\frac{7}{12}\) < \(\frac{2}{3}\).
3. Tenths: \(\frac{8}{10}\) and \(\frac{7}{10}\). \(\frac{4}{5}\) > \(\frac{7}{10}\).
4. Twelfths: \(\frac{10}{12}\) and \(\frac{11}{12}\). \(\frac{5}{6}\) < \(\frac{11}{12}\).
Answer to Question 7
1. \(\frac{19}{8}\) of a pizza.
2. 19 ÷ 8 = 2 remainder 3, so \(2\frac{3}{8}\): 2 whole pizzas and 3 more slices.
3. \(\frac{1}{4}\) = \(\frac{2}{8}\), so 2 slices.
4. The \(\frac{5}{8}\) left over is 5 slices.
Answer to Question 8
1. \(\frac{7}{4}\) = \(1\frac{3}{4}\); \(1\frac{1}{2}\) = \(\frac{3}{2}\).
2. \(\frac{7}{4}\) m and \(1\frac{3}{4}\) m are equal, since both are 1 and 3/4.
3. In quarters: \(\frac{7}{4}\), \(\frac{6}{4}\), \(\frac{5}{4}\), \(\frac{7}{4}\). Longest first: \(\frac{7}{4}\) = \(1\frac{3}{4}\), then \(1\frac{1}{2}\), then \(\frac{5}{4}\).
4. The longest is \(\frac{7}{4}\) m. Half of that is \(\frac{7}{8}\), so each half is \(\frac{7}{8}\) m.
Answer to Question 9
1. Ravi: \(\frac{6}{24}\) = \(\frac{1}{4}\). Jo: \(\frac{8}{24}\) = \(\frac{1}{3}\). Lily: \(\frac{4}{24}\) = \(\frac{1}{6}\).
2. Jo eats the most (\(\frac{8}{24}\)) and Lily the least (\(\frac{4}{24}\)).
3. Squares eaten: 6 + 8 + 4 = 18. Squares left: 24 − 18 = 6, which is \(\frac{6}{24}\) = \(\frac{1}{4}\).
4. 8 ÷ 8 = 1 and 24 ÷ 8 = 3, so \(\frac{8}{24}\) = \(\frac{1}{3}\).
Answer to Question 10
1. \(\frac{5}{4}\) = \(1\frac{1}{4}\); \(\frac{7}{3}\) = \(2\frac{1}{3}\); \(\frac{9}{2}\) = \(4\frac{1}{2}\).
2. Oats, with \(4\frac{1}{2}\) cups.
3. Multiply top and bottom of \(\frac{5}{4}\) by 2 to get \(\frac{10}{8}\). Yes, she is right.
4. \(3\frac{1}{2}\) = 3 × 2 + 1 = 7 over 2 = \(\frac{7}{2}\).
Answer to Question 11
1. \(\frac{13}{4}\) = \(3\frac{1}{4}\); \(\frac{10}{3}\) = \(3\frac{1}{3}\).
2. Ben ran \(3\frac{1}{2}\) (the most); Amy and Dee both ran \(3\frac{1}{4}\) (the least).
3. Fractional parts: \(\frac{1}{4}\), \(\frac{1}{3}\), \(\frac{1}{2}\). Order: Amy = Dee (\(3\frac{1}{4}\)), Cal (\(3\frac{1}{3}\)), Ben (\(3\frac{1}{2}\)).
4. Cal ran 3 complete laps (and one third of another).
Answer to Question 12
1. \(\frac{3}{4}\) = \(\frac{6}{8}\).
2. 6 eighths is more than 5 eighths, so the red jug holds more.
3. \(\frac{6}{8}\) − \(\frac{5}{8}\) = \(\frac{1}{8}\) litre.
4. \(\frac{6}{8}\) + \(\frac{5}{8}\) = \(\frac{11}{8}\) = \(1\frac{3}{8}\) litres.
Answer to Question 13
1. \(\frac{1}{4}\) = \(\frac{2}{8}\).
2. Books: \(\frac{3}{8}\) of £24: 24 ÷ 8 = 3, 3 × 3 = £9. Savings: \(\frac{2}{8}\) of £24 = 2 × 3 = £6.
3. \(\frac{3}{8}\) + \(\frac{2}{8}\) = \(\frac{5}{8}\), so \(\frac{3}{8}\) is left. That is 3 × 3 = £9.
4. Yes, \(\frac{3}{8}\) is more than \(\frac{2}{8}\) (£9 against £6).
Answer to Question 14
1. Walk \(\frac{12}{24}\) = \(\frac{1}{2}\); Bus \(\frac{6}{24}\) = \(\frac{1}{4}\); Car \(\frac{4}{24}\) = \(\frac{1}{6}\); Cycle \(\frac{2}{24}\) = \(\frac{1}{12}\).
2. 12 pupils do not walk: \(\frac{12}{24}\) = \(\frac{1}{2}\).
3. Walk and bus: \(\frac{12}{24}\) + \(\frac{6}{24}\) = \(\frac{18}{24}\) = \(\frac{3}{4}\).
4. \(\frac{1}{12}\) is smaller than \(\frac{1}{10}\), because twelfths are smaller pieces than tenths. Smaller.
Answer to Question 15
1. Asha \(\frac{5}{8}\); Ben \(\frac{8}{12}\); Cara \(\frac{4}{6}\); Dev \(\frac{2}{8}\).
2. Ben \(\frac{8}{12}\) = \(\frac{2}{3}\); Cara \(\frac{4}{6}\) = \(\frac{2}{3}\); Dev \(\frac{2}{8}\) = \(\frac{1}{4}\); Asha \(\frac{5}{8}\) is already simplified.
3. In twenty-fourths: Dev 6, Asha 15, Ben 16, Cara 16. So Dev, Asha, then Ben = Cara (\(\frac{1}{4}\) < \(\frac{5}{8}\) < \(\frac{2}{3}\)).
4. Ben and Cara took the most, \(\frac{2}{3}\) of a cake each. They are equal because \(\frac{8}{12}\) = \(\frac{4}{6}\).
5. First cake: 5 + 2 = 7 slices taken out of 8, so \(\frac{1}{8}\) is left.
Answer to Question 16
1. \(\frac{5}{2}\) = \(2\frac{1}{2}\); \(\frac{7}{4}\) = \(1\frac{3}{4}\); \(\frac{11}{6}\) = \(1\frac{5}{6}\); \(\frac{9}{4}\) = \(2\frac{1}{4}\).
2. \(1\frac{1}{3}\), \(\frac{7}{4}\) and \(\frac{11}{6}\).
3. The biggest is \(2\frac{3}{4}\) and the smallest is \(1\frac{1}{3}\).
4. Twelfths: \(1\frac{1}{3}\) = \(\frac{16}{12}\); \(\frac{7}{4}\) = \(\frac{21}{12}\); \(\frac{11}{6}\) = \(\frac{22}{12}\); \(\frac{9}{4}\) = \(\frac{27}{12}\); \(\frac{5}{2}\) = \(\frac{30}{12}\); \(2\frac{3}{4}\) = \(\frac{33}{12}\). Order: \(1\frac{1}{3}\), \(\frac{7}{4}\), \(\frac{11}{6}\), \(\frac{9}{4}\), \(\frac{5}{2}\), \(2\frac{3}{4}\).
5. Three: \(\frac{9}{4}\), \(\frac{5}{2}\) and \(2\frac{3}{4}\).
Answer to Question 17
1. \(\frac{47}{12}\) = 47 ÷ 12 = 3 remainder 11, so \(3\frac{11}{12}\); \(\frac{35}{12}\) = 2 remainder 11, so \(2\frac{11}{12}\).
2. \(3\frac{5}{6}\) = 3 × 6 + 5 = 23 over 6 = \(\frac{23}{6}\) = \(\frac{46}{12}\).
3. Twelfths: Friday 47, Saturday 46, Sunday 35. Friday, Saturday, Sunday (most to fewest).
4. Saturday: \(\frac{46}{12}\) pizzas means 46 slices.
5. Total twelfths: 47 + 46 + 35 = 128. 128 ÷ 12 = 10 remainder 8, so \(10\frac{8}{12}\) = \(10\frac{2}{3}\) pizzas. 12 is more than \(10\frac{2}{3}\), so yes, it is enough.
Answer to Question 18
1. \(\frac{1}{2}\) = \(\frac{6}{12}\) and \(\frac{3}{4}\) = \(\frac{9}{12}\).
2. Between \(\frac{6}{12}\) and \(\frac{9}{12}\): \(\frac{7}{12}\) and \(\frac{8}{12}\). There are 2 with denominator 12.
3. \(\frac{2}{3}\) = \(\frac{8}{12}\), which is one of those two. Yes.
4. Use twelfths: \(\frac{1}{3}\) = \(\frac{4}{12}\) and \(\frac{1}{2}\) = \(\frac{6}{12}\), so \(\frac{5}{12}\) lies between them.
5. Change both fractions to a bigger common denominator, such as 24, and there is room for more numerators in between. We can always do this.
Answer to Question 19
1. \(\frac{18}{90}\) = \(\frac{1}{5}\). (Divide top and bottom by 18.)
2. \(\frac{7}{15}\) of 90: 90 ÷ 15 = 6, 6 × 7 = 42 minutes.
3. Second half: 42 minutes compared with 18 minutes, so the second half.
4. \(\frac{60}{90}\) = \(\frac{2}{3}\).
5. 60 minutes out of 90 is \(\frac{2}{3}\), and the other team had 30 minutes, \(\frac{30}{90}\) = \(\frac{1}{3}\). Yes, he is right.
Answer to Question 20
1. \(\frac{12}{18}\) = \(\frac{2}{3}\). With denominator 10 or less: \(\frac{2}{3}\), \(\frac{4}{6}\) and \(\frac{6}{9}\).
2. If the fraction is \(\frac{2k}{5k}\), then 2k + 5k = 35, so 7k = 35 and k = 5. The fraction is \(\frac{10}{25}\).
3. 3 = \(\frac{21}{7}\) and 4 = \(\frac{28}{7}\). The fractions strictly between are \(\frac{22}{7}\) (\(3\frac{1}{7}\)), \(\frac{23}{7}\) (\(3\frac{2}{7}\)), \(\frac{24}{7}\) (\(3\frac{3}{7}\)), \(\frac{25}{7}\) (\(3\frac{4}{7}\)), \(\frac{26}{7}\) (\(3\frac{5}{7}\)) and \(\frac{27}{7}\) (\(3\frac{6}{7}\)). That is 6 fractions.

How to use these Year 5 fractions worksheet answers

First, try every question on the worksheet without looking. Then compare your working with the solution line by line, not only the final answer. When your answer is different, find the first step that changes, because that is where the mistake is. After that, read the matching part of the fractions: equivalent, mixed numbers and improper lesson again. Finally, check that the method is secure with the quiz or the test.

Also, the Year 5 fractions worksheet answers are available as a PDF, so you can mark printed work quickly. Moreover, all the pages of this chapter work together, so you can move between them at any time. For example, many pupils read the lesson on Monday, practise on Wednesday and test themselves on Friday. In short, these Year 5 fractions worksheet answers show every step, so nothing is left unexplained.

Fractions: equivalent, mixed numbers and improper – Year 5 maths worksheet answers to download as PDF

Answer to Question 1

Answer to Question 2

Answer to Question 3

Answer to Question 4

Answer to Question 5

Answer to Question 6

Answer to Question 7

Answer to Question 8

Answer to Question 9

Answer to Question 10

Answer to Question 11

Answer to Question 12

Answer to Question 13

Answer to Question 14

Answer to Question 15

Answer to Question 16

Answer to Question 17

Answer to Question 18

Answer to Question 19

Answer to Question 20

How to use these Year 5 fractions worksheet answers

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