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Adding, subtracting and multiplying fractions – Year 5 maths worksheet answers to download as PDF

Year 5 adding, subtracting and multiplying fractions worksheet answers – Otto the owl, Maths PDF
Year 5 Maths – Worksheets with Answers – PDF
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These Year 5 adding, subtracting and multiplying fractions worksheet answers give a full worked solution to all 20 questions of the adding, subtracting and multiplying fractions worksheet. Try each question yourself first, then check your method step by step.

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  1. Answer to Question 1

    1. 3 + 2 = 5, so \(\frac{3}{8}\) + \(\frac{2}{8}\) = \(\frac{5}{8}\) = \(\frac{5}{8}\).
    2. 7 − 3 = 4, so \(\frac{7}{10}\) − \(\frac{3}{10}\) = \(\frac{4}{10}\) = \(\frac{2}{5}\).
    3. 5 + 4 = 9, so \(\frac{5}{6}\) + \(\frac{4}{6}\) = \(\frac{9}{6}\) = \(1\frac{1}{2}\).
    4. 11 − 5 = 6, so \(\frac{11}{12}\) − \(\frac{5}{12}\) = \(\frac{6}{12}\) = \(\frac{1}{2}\).
  2. Answer to Question 2

    1. Common denominator 4: \(\frac{1}{2}\) + \(\frac{1}{4}\) = \(\frac{2}{4}\) + \(\frac{1}{4}\) = \(\frac{3}{4}\).
    2. Common denominator 8: \(\frac{3}{4}\) + \(\frac{1}{8}\) = \(\frac{6}{8}\) + \(\frac{1}{8}\) = \(\frac{7}{8}\).
    3. Common denominator 6: \(\frac{2}{3}\) + \(\frac{1}{6}\) = \(\frac{4}{6}\) + \(\frac{1}{6}\) = \(\frac{5}{6}\).
    4. Common denominator 6: \(\frac{5}{6}\) − \(\frac{1}{3}\) = \(\frac{5}{6}\) − \(\frac{2}{6}\) = \(\frac{1}{2}\).
    5. Common denominator 10: \(\frac{7}{10}\) − \(\frac{2}{5}\) = \(\frac{7}{10}\) − \(\frac{4}{10}\) = \(\frac{3}{10}\).
  3. Answer to Question 3

    1. Whole numbers: 1 + 2 = 3. Fractions: \(\frac{1}{4}\) + \(\frac{1}{4}\) = \(\frac{1}{2}\). Answer: \(3\frac{1}{2}\).
    2. Whole numbers: 2 + 1 = 3. Fractions: \(\frac{3}{5}\) + \(\frac{4}{5}\) = \(1\frac{2}{5}\). Answer: \(4\frac{2}{5}\).
    3. Whole numbers: 3 + 2 = 5. Fractions: \(\frac{1}{2}\) + \(\frac{1}{4}\) = \(\frac{3}{4}\). Answer: \(5\frac{3}{4}\).
  4. Answer to Question 4

    1. \(4\frac{3}{4}\) − \(1\frac{1}{4}\) = \(3\frac{1}{2}\). Check: \(3\frac{1}{2}\) + \(1\frac{1}{4}\) = \(4\frac{3}{4}\).
    2. \(5\frac{1}{2}\) − \(2\frac{3}{4}\) = \(2\frac{3}{4}\). Check: \(2\frac{3}{4}\) + \(2\frac{3}{4}\) = \(5\frac{1}{2}\).
    3. 3 − \(1\frac{2}{5}\) = \(1\frac{3}{5}\). Check: \(1\frac{3}{5}\) + \(1\frac{2}{5}\) = 3.
  5. Answer to Question 5

    1. 3 × 2 = 6, so the answer is \(\frac{6}{5}\) = \(1\frac{1}{5}\).
    2. 4 × 3 = 12, so the answer is \(\frac{12}{8}\) = \(1\frac{1}{2}\).
    3. 6 × 1 = 6, so the answer is \(\frac{6}{4}\) = \(1\frac{1}{2}\).
    4. 5 × 2 = 10, so the answer is \(\frac{10}{3}\) = \(3\frac{1}{3}\).
  6. Answer to Question 6

    1. 3 × 1 = 3 and 3 × \(\frac{1}{2}\) = \(1\frac{1}{2}\). Add: \(4\frac{1}{2}\).
    2. 4 × 2 = 8 and 4 × \(\frac{1}{4}\) = 1. Add: 9.
    3. 2 × 3 = 6 and 2 × \(\frac{2}{5}\) = \(\frac{4}{5}\). Add: \(6\frac{4}{5}\).
  7. Answer to Question 7

    1. \(\frac{3}{8}\) + \(\frac{5}{8}\) = \(\frac{8}{8}\) = 1 whole pizza.
    2. \(\frac{1}{4}\) = \(\frac{2}{8}\).
    3. 1 − \(\frac{2}{8}\) = \(\frac{8}{8}\) − \(\frac{2}{8}\) = \(\frac{6}{8}\) = \(\frac{3}{4}\) of a pizza.
    4. \(\frac{6}{8}\) − \(\frac{2}{8}\) = \(\frac{4}{8}\) = \(\frac{1}{2}\) of a pizza.
  8. Answer to Question 8

    1. \(1\frac{3}{4}\) = \(1\frac{6}{8}\); \(2\frac{1}{2}\) = \(2\frac{4}{8}\); \(\frac{5}{8}\) stays the same.
    2. Whole numbers: 1 + 2 = 3. Eighths: 6 + 4 + 5 = 15, which is \(\frac{15}{8}\) = \(1\frac{7}{8}\). Total: 3 + \(1\frac{7}{8}\) = \(4\frac{7}{8}\) m.
    3. \(6\frac{1}{4}\) = \(6\frac{2}{8}\). \(6\frac{2}{8}\) − \(4\frac{7}{8}\) = \(1\frac{3}{8}\) m.
    4. 8 × \(\frac{5}{8}\) = \(\frac{40}{8}\) = 5 m.
  9. Answer to Question 9

    1. Oats: 4 × \(\frac{3}{4}\) = \(\frac{12}{4}\) = 3. Syrup: 4 × \(\frac{2}{3}\) = \(\frac{8}{3}\) = \(2\frac{2}{3}\). Raisins: 4 × \(1\frac{1}{2}\) = 4 + 2 = 6.
    2. 3 + \(2\frac{2}{3}\) = \(5\frac{2}{3}\) cups.
    3. He needs 6 cups and has 5, so no: he is 1 cup short.
  10. Answer to Question 10

    1. Whole numbers: 2 + 1 + 3 = 6. Fractions: \(\frac{2}{4}\) + \(\frac{3}{4}\) + \(\frac{1}{4}\) = \(\frac{6}{4}\) = \(1\frac{1}{2}\). Total: 6 + \(1\frac{1}{2}\) = \(7\frac{1}{2}\) km.
    2. \(7\frac{1}{2}\) − 2 = \(5\frac{1}{2}\) km.
    3. Total so far: \(7\frac{1}{2}\) + \(5\frac{1}{2}\) = 13 km. That is already more than 10 km, so she has already beaten the goal by 3 km.
    4. 3 × \(\frac{2}{5}\) = \(\frac{6}{5}\) = \(1\frac{1}{5}\) km.
  11. Answer to Question 11

    1. \(1\frac{3}{4}\) + \(2\frac{1}{4}\) = 3 + \(\frac{4}{4}\) = 4 litres.
    2. \(4\frac{1}{2}\) − 4 = \(\frac{1}{2}\) litre.
    3. \(\frac{1}{2}\) litre is less than \(1\frac{1}{2}\) litres, so no, he is 1 litre short.
    4. 3 × \(\frac{3}{4}\) = \(\frac{9}{4}\) = \(2\frac{1}{4}\) litres.
  12. Answer to Question 12

    1. 7 × \(\frac{2}{3}\) = \(\frac{14}{3}\) = \(4\frac{2}{3}\) litres.
    2. 7 × \(\frac{1}{3}\) = \(2\frac{1}{3}\) litres.
    3. \(4\frac{2}{3}\) + \(2\frac{1}{3}\) = 6 + \(\frac{3}{3}\) = 7 litres. (Also each child drinks \(\frac{2}{3}\) + \(\frac{1}{3}\) = 1 litre, and 7 × 1 = 7.)
    4. 10 − 7 = 3 litres are left.
  13. Answer to Question 13

    1. \(3\frac{1}{2}\) − \(1\frac{3}{4}\) = \(3\frac{2}{4}\) − \(1\frac{3}{4}\) = \(2\frac{6}{4}\) − \(1\frac{3}{4}\) = \(1\frac{3}{4}\) m.
    2. \(1\frac{3}{4}\) + \(2\frac{1}{4}\) = 4 m.
    3. 4 × \(1\frac{3}{4}\) = 4 + 3 = 7 m.
    4. She has \(3\frac{1}{2}\) m red and \(2\frac{1}{4}\) m blue = \(5\frac{3}{4}\) m. That is less than 7 m, so no.
  14. Answer to Question 14

    1. \(\frac{1}{4}\) = \(\frac{2}{8}\).
    2. \(\frac{2}{8}\) + \(\frac{3}{8}\) = \(\frac{5}{8}\) of the tank.
    3. \(\frac{7}{8}\) − \(\frac{5}{8}\) = \(\frac{2}{8}\) = \(\frac{1}{4}\) of the tank.
    4. 800 ÷ 8 = 100 litres is \(\frac{1}{8}\) of 800. So \(\frac{2}{8}\) = 200 litres are left.
  15. Answer to Question 15

    1. Carrots: 3 × \(1\frac{1}{2}\) = 3 + \(\frac{3}{2}\) = \(4\frac{1}{2}\) kg. Potatoes: 3 × \(\frac{3}{4}\) = \(\frac{9}{4}\) = \(2\frac{1}{4}\) kg. Stock: 3 × \(2\frac{1}{4}\) = 6 + \(\frac{3}{4}\) = \(6\frac{3}{4}\) litres. Lentils: 3 × \(\frac{5}{8}\) = \(\frac{15}{8}\) = \(1\frac{7}{8}\) kg.
    2. \(4\frac{1}{2}\) + \(2\frac{1}{4}\) = 6 + \(\frac{3}{4}\) = \(6\frac{3}{4}\) kg.
    3. He already has \(5\frac{1}{2}\) kg. He needs \(2\frac{1}{4}\) kg. So he has enough: he needs no more, and has \(3\frac{1}{4}\) kg extra.
    4. Half of \(2\frac{1}{4}\) litres: \(2\frac{1}{4}\) = \(\frac{9}{4}\), half of that is \(\frac{9}{8}\) = \(1\frac{1}{8}\) litres.
    5. \(1\frac{7}{8}\) is less than 2, because 2 = \(1\frac{8}{8}\). Less, by \(\frac{1}{8}\) kg.
  16. Answer to Question 16

    1. \(\frac{2}{8}\) + \(\frac{3}{8}\) + \(\frac{1}{8}\) = \(\frac{6}{8}\) = \(\frac{3}{4}\).
    2. 1 − \(\frac{6}{8}\) = \(\frac{2}{8}\) = \(\frac{1}{4}\).
    3. \(\frac{1}{4}\) of 240 = 240 ÷ 4 = 60 pages.
    4. \(\frac{3}{8}\) of 240: 240 ÷ 8 = 30, 30 × 3 = 90 pages.
    5. The rest is exactly \(\frac{1}{4}\) of the book, so yes, she is right.
  17. Answer to Question 17

    1. 7 − 3 = 4, so \(\frac{4}{8}\).
    2. Write \(\frac{1}{2}\) as \(\frac{2}{4}\). 3 − 2 = 1, so \(\frac{1}{4}\).
    3. \(\frac{1}{2}\) = \(\frac{6}{12}\), and 11 − 6 = 5, so \(\frac{5}{12}\).
    4. Write \(\frac{9}{2}\) as \(\frac{18}{4}\). The numerator 18 divided by 3 is 6, so 6 × \(\frac{3}{4}\) = \(\frac{18}{4}\). The missing number is 6.
    5. Subtract: \(5\frac{1}{4}\) − \(3\frac{1}{2}\) = \(5\frac{1}{4}\) − \(3\frac{2}{4}\) = \(1\frac{3}{4}\).
  18. Answer to Question 18

    1. 3 × \(2\frac{3}{4}\) = 6 + \(\frac{9}{4}\) = 6 + \(2\frac{1}{4}\) = \(8\frac{1}{4}\) m.
    2. 2 × \(\frac{5}{8}\) = \(\frac{10}{8}\) = \(1\frac{1}{4}\) m.
    3. \(8\frac{1}{4}\) + \(1\frac{1}{4}\) = \(9\frac{1}{2}\) m.
    4. 10 − \(9\frac{1}{2}\) = \(\frac{1}{2}\) m.
    5. \(\frac{1}{2}\) m is less than \(2\frac{3}{4}\) m, so no, he is \(2\frac{1}{4}\) m short.
  19. Answer to Question 19

    1. 3 × \(3\frac{1}{2}\) = 9 + \(\frac{3}{2}\) = 9 + \(1\frac{1}{2}\) = \(10\frac{1}{2}\) km.
    2. 2 × \(3\frac{1}{2}\) = 7 km, and 7 + \(\frac{3}{4}\) = \(7\frac{3}{4}\) km.
    3. \(10\frac{1}{2}\) − \(7\frac{3}{4}\) = \(10\frac{2}{4}\) − \(7\frac{3}{4}\) = \(9\frac{6}{4}\) − \(7\frac{3}{4}\) = \(2\frac{3}{4}\). Maya runs \(2\frac{3}{4}\) km further.
    4. Total: \(10\frac{1}{2}\) + \(7\frac{3}{4}\) = \(18\frac{1}{4}\) km. 20 − \(18\frac{1}{4}\) = \(1\frac{3}{4}\) km.
    5. 6 × \(3\frac{1}{2}\) = 21 km each. Together they run 42 km, which is more than 40 km: yes.
  20. Answer to Question 20

    1. \(\frac{1}{2}\) = \(\frac{3}{6}\) and \(\frac{1}{3}\) = \(\frac{2}{6}\). \(\frac{3}{6}\) + \(\frac{2}{6}\) = \(\frac{5}{6}\).
    2. \(\frac{7}{8}\) = \(\frac{4}{8}\) + \(\frac{2}{8}\) + \(\frac{1}{8}\) = \(\frac{1}{2}\) + \(\frac{1}{4}\) + \(\frac{1}{8}\).
    3. \(\frac{2}{3}\) = \(\frac{4}{6}\) = \(\frac{3}{6}\) + \(\frac{1}{6}\). So \(\frac{1}{2}\) + \(\frac{1}{6}\).
    4. 1 = \(\frac{6}{6}\) = \(\frac{3}{6}\) + \(\frac{2}{6}\) + \(\frac{1}{6}\) = \(\frac{1}{2}\) + \(\frac{1}{3}\) + \(\frac{1}{6}\).

How to use these Year 5 adding, subtracting and multiplying fractions worksheet answers

First, try every question on the worksheet without looking. Then compare your working with the solution line by line, not only the final answer. When your answer is different, find the first step that changes, because that is where the mistake is. After that, read the matching part of the adding, subtracting and multiplying fractions lesson again. Finally, check that the method is secure with the quiz or the test.

Also, the Year 5 adding, subtracting and multiplying fractions worksheet answers are available as a PDF, so you can mark printed work quickly. Moreover, all the pages of this chapter work together, so you can move between them at any time. For example, many pupils read the lesson on Monday, practise on Wednesday and test themselves on Friday. In short, these Year 5 adding, subtracting and multiplying fractions worksheet answers show every step, so nothing is left unexplained.